Peter

Welcome to the forum… not sure about Joules as we here in US go by weight the bow pulls. Not by Ft lbs of energy? 35 Lb bow and 500gr plus arrows( with Razor Sharp bhead ) and up,  are usually preferred here….

I have no experience with the hoyt satori, so can’t say …

Maybe Steve will comment..

Scout aka Ray

Greetings from S.E. Arizona

This is taxing my math skills to the max so if I’ve got it wrong somebody PLEASE let me know.

As I understand it, a Joule is 0.7377 foot pounds. 80 of them would be 59.02 foot pounds. Using the numbers for my 60# Super Diablo, with a 500 grain arrow at 190 fps, I’m getting 40.07 foot pounds. Mass in grains X V X V divided by 450437. Or in other words not enough Joules by a bunch ??  Doesn’t seem right ………….. unless I hit a shoulder blade or big bone I tend to blow thru deer sized critters completely.  Either I’ve got something wrong or whoever wrote your game law doesn’t have a clear understanding of archery.  Possibly both.

Is there a Rocket Scientist in the building ??????

This has got my brain housing group scrambled. In the words of the Philosopher Fudd  “There’s something screwy going on here”.

Is it possible that when they say 80 Joules (59.02 foot pounds) that they are referring to the draw weight of the bow and not the energy of the arrow at one foot ????  That would make more sense but that’s a pretty stout stick and not a poundage I would recommend for a beginner or a casual shooter.

and;

When you say 33 gr. can we assume that’s Grams and not Grains ???  The Metric System is not my strong suit.

And;

Last but not least, I think that most of us here would really like to hear about archery in Denmark. The rounds that you shoot, the history and the critters you can hunt.

Wow.  That would leave me completely out of hunting.  I have a 60# Great Northern Bushbow that I can’t even string anymore because the Moderna Covid vaccine screwed up my muscles.  I used to shoot up to 72# draw but 85# would still be too much back then.

Hey guys, sorry for the late reply.  Been super busy on the farm.

So Joules is a measure of energy.  The question is, is this a requirement of the arrow in flight, or the energy stored in the bow at full draw?

I will assume the requirement is for energy stored in a bow.  To measure the energy stored in the bow, you can graph the draw curve.  The area under the draw curve is the energy stored in the bow.  This means that the energy stored is a function of both draw length, and draw weight.  Not only that, it depends on the shape of the curve.  If the bow gets to draw weight in the first few inches and stays there, then you have compound bow level energies.  If it is wilty and increases slowly only to stack up at the end, there will be little area under the curve and the bow will be a dog.

Here is an interesting article that explains it with pictures: https://aharchery.com/?page_id=21273.  Their example is for a bow with a 30 inch draw length and a draw weight of 60 lbs.  The energy stored was around 51ftlbs.  80 Joules is equivalent to about 59ftlbs.  This means you would need a bow over 60lbs to meet that requirement.

You can’t know the energy stored without knowing the draw length or the shape of the draw curve.

Using common sense, this is a stupid requirement for small game.  Anyone with a lick of common sense knows you don’t need a 60lb bow to kill a rabbit or deer.  Maybe the folks in charge need some education on bow hunting?

In my experience, there is another way to solve the problem.  Just write the required energy on the side of the bow.  If its written, it must be so.  Right? Hmm…..

Stefan

Thanks for the info and explanation…

I particularly like the part about ” writing it on the bow ” ….perfect solution

Scout aka Ray